24x^2+157x+222=0

Solution for 24x^2+157x+222=0 equation:

24x^2+157x+222=0

a = 24; b = 157; c = +222;
Δ = b2-4ac
Δ = 1572-4·24·222
Δ = 3337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(157)-\sqrt{3337}}{2*24}=\frac{-157-\sqrt{3337}}{48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(157)+\sqrt{3337}}{2*24}=\frac{-157+\sqrt{3337}}{48}
$